// IsPalindrome.groovy, ©2017 by Josh Moyer <JMoyer@NODOMAIN.NET>
// All rights reserved.

def Palindrome(theString)
{
	def strLen = theString.length()
	def i
	def oppIndex
	def currentChar

	if (strLen == 0) return Result.Null
	for (i = 0 ; i < strLen / 2 ; i++)
	{
		currentChar = theString.charAt(i)
		oppIndex = strLen - i 
		if (currentChar == theString.charAt(oppIndex -1)) continue
		else return Result.Not
	}
	return Result.Is
}

def enum Result
{
	Is,
	Not,
	Null
}

class TestCase
{
	def TestInput
	def TestResult
	def TestCase(Input, Result)
	{
		TestInput = Input
		TestResult = Result
	}
}
	
def CurrentResult

TestCase[] TestCases = [
	new TestCase('', Result.Null),
	new TestCase(' ', Result.Is),
	new TestCase('  ', Result.Is),
	new TestCase('   ', Result.Is),
	new TestCase('A', Result.Is),
	new TestCase('AA', Result.Is),
	new TestCase('AB', Result.Not),
	new TestCase('AAA', Result.Is),
	new TestCase('AAB', Result.Not),
	new TestCase('ABA', Result.Is),
	new TestCase('radar', Result.Is),
	new TestCase('Radar', Result.Not),
	new TestCase('Rädar', Result.Not),
	new TestCase('1', Result.Is),
	new TestCase('12', Result.Not),
	new TestCase('123', Result.Not),
	new TestCase('121', Result.Is)
	]
	
for (CurrentCase in TestCases)
{
	CurrentResult = Palindrome(CurrentCase.TestInput)
	
	if (CurrentResult == CurrentCase.TestResult) continue
	else println CurrentCase.TestInput + ' failed test.'
}